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Multiple Choice

True or False: Including Zs after the last letter ensures the upper bound is after all names starting with that letter.

When you want to include all names that start with a given letter in a range, you can set the upper bound by appending the highest possible character(s) after that letter. In the common A–Z ordering, Z is the highest, so adding Zs after the last letter makes the upper bound sit after every string that begins with that letter. Why this works: any name starting with that letter will be identical up to the first character, and whatever follows will be between the letter and Z (or nothing at all). The string with the extra Zs is lexicographically larger than all those possibilities, so the range from the letter itself up to that letter plus trailing Zs will capture every name beginning with that letter. For example, with the letter A, lower bound "A" and upper bound "AZZZ" will include "A", "Aaron", "Alex", "AZ", "AZZ", and any other continuation starting with A, but nothing that starts with a later letter. So the statement is True.

When you want to include all names that start with a given letter in a range, you can set the upper bound by appending the highest possible character(s) after that letter. In the common A–Z ordering, Z is the highest, so adding Zs after the last letter makes the upper bound sit after every string that begins with that letter.

Why this works: any name starting with that letter will be identical up to the first character, and whatever follows will be between the letter and Z (or nothing at all). The string with the extra Zs is lexicographically larger than all those possibilities, so the range from the letter itself up to that letter plus trailing Zs will capture every name beginning with that letter. For example, with the letter A, lower bound "A" and upper bound "AZZZ" will include "A", "Aaron", "Alex", "AZ", "AZZ", and any other continuation starting with A, but nothing that starts with a later letter.

So the statement is True.